Lời giải:
a) sin 40o12' ≈ 0,6455
b) cos52o54' ≈ 0,6032
c) tan63o36' ≈ 2,0145
d) cot25o18' ≈ 2,1155
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Lời giải:
a) sin 40o12' ≈ 0,6455
b) cos52o54' ≈ 0,6032
c) tan63o36' ≈ 2,0145
d) cot25o18' ≈ 2,1155
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