Câu 70 Trang 40: Biến đổi, rút gọn biểu thức
- David Smith
- February 10, 2022
- 15 min Read
- 2 comments
Ta có :
a. $\sqrt{\frac{25}{81}.\frac{16}{49}.\frac{196}{9}}$
= $\sqrt{\frac{25}{81}}.\sqrt{\frac{16}{49}}.\sqrt{\frac{196}{9}}$
= $\frac{5}{9}.\frac{4}{7}.\frac{14}{3}=\frac{5.4.14}{9.7.3}=\frac{40}{27}$
Vậy $\sqrt{\frac{25}{81}.\frac{16}{49}.\frac{196}{9}}=\frac{40}{27}$
b. $\sqrt{3\frac{1}{16}.2\frac{14}{25}.2\frac{34}{81}}$
= $\sqrt{\frac{49}{16}.\frac{64}{25}.\frac{196}{81}}$
= $\sqrt{\frac{49}{16}}.\sqrt{\frac{64}{25}}.\sqrt{\frac{196}{81}}$
= $\frac{7}{4}.\frac{8}{5}.\frac{14}{9}=\frac{196}{45}$
Vậy $\sqrt{3\frac{1}{16}.2\frac{14}{25}.2\frac{34}{81}}=\frac{196}{45}$
c. $\frac{\sqrt{640}.\sqrt{34,3}}{\sqrt{567}}$
= $\sqrt{\frac{640.34,3}{567}}$
= $\sqrt{\frac{64.49}{81}}$
= $\frac{\sqrt{64}.\sqrt{49}}{\sqrt{81}}$
= $\frac{8.7}{9}=\frac{56}{9}$
Vậy $\frac{\sqrt{640}.\sqrt{34,3}}{\sqrt{567}}=\frac{56}{9}$
d. $\sqrt{21,6}.\sqrt{810}.\sqrt{11^{2}-5^{2}}$
= $\sqrt{21,6.810.(11^{2}-5^{2})}$
= $\sqrt{216.81.(11+5)(11-5)}$
= $\sqrt{36^{2}.9^{2}.4^{2}}=36.9.4=1296$
Vậy $\sqrt{21,6}.\sqrt{810}.\sqrt{11^{2}-5^{2}}=1296$